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20x^2-37x-14=0
a = 20; b = -37; c = -14;
Δ = b2-4ac
Δ = -372-4·20·(-14)
Δ = 2489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{2489}}{2*20}=\frac{37-\sqrt{2489}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{2489}}{2*20}=\frac{37+\sqrt{2489}}{40} $
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